Question

what is the second order derivative of sin 2x.tan 10x?

Answer 1

do you know what the first is?

(hint: you'll need product rule and chain rule)

Answer 2

or maybe the answer you want is just: the second derivative is the derivative of the first derivative

Answer 3

\[\frac{ d(\sin ^{2}x)(d(sinx) d(\tan10x) }{ dx }\]

take the derivate of each case..

Answer 4

Alright here is the first one figure out the second..

\[2(sinx)(cosx)(10\sec ^{2}10x)\]