Question

find
(z-8)^4/3=2

Where z is a real number...

Answer 1

\[(z-8)^{4/3}=2 \rightarrow (z-8)=2^{3/4} \rightarrow z-8=\sqrt[4]{2^{3}}\]
i.e. \[z-8=\sqrt[4]{8} \rightarrow z=8+\sqrt[4]{8}\]