Question

solve for variables in the equation below
12^(y+2)=6
e^x=11


Round your answers to the nearest hundredth.
Do not round any intermediate computations.

Answer 1

@pkamania

Answer 2

1.
Take log to (base 12) on both sides to get
log(base 12)12^(y+2)=log(base 12)6=log(6)/log(12)
y+2 = log(6)/log(12)
Solve for y.

2. Same as 1, but take log to base e (natural log)
log(base e)e^x = log(base e) 11
x = log(base e) 11