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Find the product. 3y^2 z(2y^2 z + 4yz - y + z) =6y^(4z) + 12y^(1+2z)z - 3y^(1+2z) + 3zy^(2z)?
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\[3y^2z(2y^2z+4yz-y+z)\] Is this your question?
yes
You have your grouping wrong in your answer which may not be the answer you have written on paper.
Multiply the whole bracket with 3y^2z 3y^2 z(2y^2 z + 4yz - y + z) 6y^4z^2+12y^3z^2-3y^3z+3y^2z^2
Reads like this: \[6y^{4z} + 12y^{1+2z}z - 3y^{1+2z} + 3zy^{2z}\]
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o h i see what i did thank you
Uri's answer is correct. And looks like this: \[3y^2 z(2y^2 z + 4yz - y + z)\] \[6y^4z^2+12y^3z^2-3y^3z+3y^2z^2\]
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