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Help please! P(x)=150(1.07)^x where x is the number of years since 1995. in which year will the population reach 300
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a)2005 b)2028 c)2016 d)2026
sorry b is incorrect its 2038
well let P(x) =300 so \[300 = 150(1.07)^x\] divide both sides of the equation by 150. take the log of both sides this should make it easier for find x, you'll just need to apply the log law for powers \[\log(x^a) = alog(x)\]
i got 2005?
seems a sensible answer
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