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Precalculus 14 Online
OpenStudy (anonymous):

simplify: cosh(arcsinh(x))

OpenStudy (anonymous):

square root of 1 + sinh^2x

OpenStudy (anonymous):

...?

OpenStudy (anonymous):

That's the answer

OpenStudy (anonymous):

oh thanks, but how? what were the steps?

OpenStudy (anonymous):

was this a stupid question?

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