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What is the maximum or minimum value of 100x^2-1700x? Please help, online test due tonight
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here at OS it is requested that you dont post test/exam questions :D
Well, he said I could use every resource I have lol
ah well that is alright :D
could you help me?
nope sorry @mathstudent55
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if you take the derivative then set the equation to = 0 then solve you will have a max or min \[\frac{d}{dx} 100x^2-1700x = 200x-1700\]now we need to set F(x) to zero then solve for x \[200x - 1700=0\]\[200x = 1700\]\[x = \frac{1700}{200}\]
in our case since we are positive we have a min
and also if you graph the function you can see the min
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