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Square Root 2y-1-1=2 What is the root?
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The answers are Y=5 Y=4 or None
Do you mean \(\sqrt{2y-1}-1=2\)?
i do
First isolate the radical (part under the square root) by adding 1 to both sides: \[\sqrt{2y-1} = 3\]
ok
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I do? may I be the man of honor?
yes
heheh
Then, square both sides: \[2y-1 = 9\] And solve for y.
so y = 5?
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