Question

how do i solve this 16 < 2x + 4 < 4 ?

Answer 1

You want to isolate the 2x in the middle first...so subtract 4 from all sides of the equation

\[\large 16 - 4 < 2x + 4 -4 < 4 - 4\]

this now becomes

\[\large 12 < 2x < 0\]

Now you want to solve for 'x'...not 2x....so divide everything by 2...

\[\large \frac{12}{2} < \frac{2x}{2} < \frac{0}{2}\]

And this becomes...

\[\large ? < x < \space ?\]