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how do you factor y^2-81
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Do you recognize the pattern: \(a^2 - b^2 = (a + b)(a - b) \) ?
yeah
This is called factoring "a difference of trwo squares."
\( y^2 - 81\) \( = y^2 - 9^2\) Now follow the pattern. What do you get?
y^2-72y-81<-is the answer
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(y+9) (y-9) is the factor?
The second one.
okay thanks!
wlcm
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