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Mathematics 19 Online
OpenStudy (anonymous):

factor 4n^3-5n^2+n

OpenStudy (anonymous):

\[n(4n^2-5n+1)\]

OpenStudy (anonymous):

n(4n^2-5n+1) n(4n-1)(n-1)

OpenStudy (anonymous):

\[n(4n^2-4n-n+1)\] you can do further

OpenStudy (anonymous):

thank you both!!

OpenStudy (anonymous):

np

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