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if a^2+b^2=7ab then log(a+b)/3 is equal to
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a^2+b^2+2ab = 9ab (a+b)^2=9ab taking log 2log (a+b )= log 9 + log a +log b 2log(a+b)-2log3 = log a + log b 2log(a+b)/3= log a + log b log (a+b)/3= log(ab)/2
oh i didnt realize the 3 was inside the log :{
thankz all
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