Question

What is the ratio of the area of TRIANGLE ABC to the area of sector BDCA (the sector spanned by arc BDC)?
see comments for diagram

Answer 1

The ratio is:\[ratio=\frac{ A _{ABC} }{ A _{BDCA} }=\frac{ \frac{ r^{2} }{ 2 } }{ \frac{ 3 }{ 4 }\pi r^2 }=\frac{ 4 }{ 6\pi }=\frac{ 2 }{ 3\pi }=0.21\]

Answer 2

thank you so much