solve 3(x+4)-4(x+3)=7x+16 1: x=3 2: x=2 3: x=-2
distribute through all of the parenthesis
man ive been on this question for like 15 min i dont it
dont get it*
3(x + 4) - 4(x + 3) = 7x + 16 3x + 12 - 4x - 12 = 7x + 16 are you with me so far ?
yes
now we will combine like terms -x = 7x + 16 still with me ?
kpajon are you writing a love letter?
oh yeah
.......
In this situation you have to input the three solutions. 1. 3(3+4)-4(3+3)=7(3)+16 3(7)-4(6)=21+16 21-24=37 -3 does not equal 37, therefore it is not a solution. 2. 3(2+4)-4(2+3)=7(2)+16 3(6)-4(5)=14+16 18-20=30 -2 does not equal 30, therefore it is not a solution. 3. 3(-2+4)-4(-2+3)=7(-2)+16 3(2)-4(1)=-14+16 6-4=2 2 does equal 2, therefore -2 is the solution.
lol you better love me after I did all that work -.-
-x = 7x + 16 subtract 7x from both sides -x - 7x = 16 -8x = 16 x = -16/8 x = -2 check... 3(x + 4) - 4(x + 3) = 7x + 16 3(-2 + 4) - 4(-2 + 3) = 7(-2) + 16 3(2) - 4(1) = -14 + 16 6 - 4 = -14 + 16 2 = 2 (correct) any questions ?
ty for the ANSWER!
lol -2 or 2
-2
oh nvm
The solution is -2
you do not need to plug in all solutions to find the answer....just solve for x.
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