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Mathematics 16 Online
OpenStudy (anonymous):

Factor completely: 3x^2 + 2x − 1 (3x + 1)(x − 1) (3x + 1)(x + 1) (3x − 1)(x + 1) (3x − 1)(x − 1)

OpenStudy (ivettef365):

the last number is -1, so in order to be negative when you multiply, you need a negative and a positive, that will eliminate answer 2 and 4

OpenStudy (uri):

3x^2+3x-x-1 3x(x+1)-1(x+1)

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