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Solve the system of linear equations x − 2y + 3z = −1 4x + 5y + z = 0 −x + y − 2z = 1 What is the value of z?
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Equation 1 + Equation 2 gives you the result -y + z = 0 Which means y = z This can be equation 4 Equation 2 + (4 * Equation 3) gives you the result 9y -7z = 4 then if you This can be equation 5 substitute equation 4 into equation 5 you get 2z = 4 so z = 2
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