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solve \[\sqrt{3x-2}\le2 \]
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@mathstudent55 hey come
what would the answer be? i gotta zip through these i dont want you to have to leave i got two others after this one and then im done :D
Change the inequality into an equation: \(\sqrt{3x - 2} = 2 \) and solve for x. Start be squaring both sides.
i dont know what to do can you please just solve it for me
@mathstudent55 can you come back and solve it for me pleaseee
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please math im really depending on you your like crazy smart <3
3x - 2 = 4 3x = 6 x = 2 There is one point of interst, x = 2. Now look at the root. Solve 3x - 2 = 0 3x = 2 x = 2/3 Here is another point of interest, x = 2/3. Now plot them on a number line.
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