Question

Find the zeros of the equation.

2x^2-x=10+y

A. x=2 and x=-5/2
B. x=-2 and x=5/2
C. x=2 and x=-2/5

Answer 1

Set y equal to zero and use the quadratic formula.

Answer 2

\[2x^2-x-10=0\]
\[ax^2+bx+c\]
\[x= \frac{ -b \pm \sqrt(b^2-4ac) }{ 2a }\]

Answer 3

\[x = \frac{ 1 \pm \sqrt(1^2+4(2)(10)) }{ 2(2) } = -2; \frac{ 5 }{ 2 }\]