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Describe the usefulness of the conjugate and its effect on other complex numbers
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\[\frac{ 2 }{ 4-i }* \frac{ 4+i }{ 4+i } = \frac{ 8+2i }{ 16+1 } = \frac{ 8+2i }{ 17 }\]
It gets rid of the complex number on the bottom.
If you are trying to find the magnitude of some value, it is much easier to solve if you have the complex part in the numerator.
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