Question

Perform the indicated operation.

3k/k-2 + 6/2-k =

1) 3
2) -3
3) 3k+6/k-2
4) 3k+6/k+2

Answer 1

\[\frac{3k}{k-2}+\frac{6}{2-k}\] can be rewritten as
\[\frac{3k}{k-2}-\frac{6}{x-2}\] now that the denominators are the same, subtract in the numerator

Answer 2

once you get
\[\frac{3k-6}{k-2}\] you can factor the numerator, then cancel
\[\frac{3k-6}{k-2}=\frac{3(k-2)}{k-2}=\frac{3\cancel{(k-2)}}{\cancel{k-2}}=3\]