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Help!!! will give medal:) :) solve for x
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|dw:1375209081340:dw|
do I just do 9+3=15+x??
@thomaster @Preetha @mathmate @stgreen
ACE ~ BCD
cross multiply you have 15/24 = x/x+3
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Now you can use BC/AC=CD/CE 15/24/=x/x+3
so it will look like\[\frac{ 15 }{ 24 }=\frac{ x+3 }{ x}\] and just cross multiply
No it will be BC/AC=CD/CE not BC/AC=CE/CD
Ok thanks for the help :)
Np anyway can you tell the rule by which the two triangles are similar?
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