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Mathematics 18 Online
OpenStudy (anonymous):

Help!!! will give medals:) :) find lengths x and y

OpenStudy (anonymous):

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OpenStudy (anonymous):

do I take\[\frac{ 39 }{ x }=\frac{ 52 }{ 40 }\] cross multiply to get x \[\frac{ 52 }{ 40 }=\frac{ y }{ 50 }\] cross multiply to get y???

OpenStudy (anonymous):

From the number's you gave multiplying 39*40/52=30 so x should be 30. 52*50/40=Y

OpenStudy (anonymous):

y=65

OpenStudy (anonymous):

Yep

OpenStudy (anonymous):

alright thanks so much for the help

OpenStudy (anonymous):

Yep no problem :)

OpenStudy (ivettef365):

first find y, cross multiply y/52+y = 50/90

OpenStudy (anonymous):

u mean \[\frac{ y }{ 52+y }=\frac{ 50 }{ 90 }\] and solve for y....how you get 90 @ivettef365

OpenStudy (ivettef365):

50 + 40 = 90

OpenStudy (anonymous):

ooh ok

OpenStudy (ivettef365):

when you get value of y, you can solve for x

OpenStudy (anonymous):

so y=28?

OpenStudy (ivettef365):

cross multiply, you have 90(y) = 50 (52 + y) 90y = 2600 + 50y -50y -50y ----------------- 40y = 2600 now divide 2600/40 ???

OpenStudy (anonymous):

ooh I messed up on my math so y=65

OpenStudy (ivettef365):

correct, now to find value of x, you cross multiply again but need to add all 3 numbers so you have 39 / (39+52+65) = x / (x+40+50) which is the same as 39 / 156 = x / x+ 90

OpenStudy (anonymous):

Ok I think I got it from here thanks for ur help :)

OpenStudy (ivettef365):

yw :)

OpenStudy (anonymous):

i get 86 for x @ivettef365 is that correct

OpenStudy (ivettef365):

lets see 156x = 39(x+90) 156x = 39x + 3510 -39x -39x ------------------ 117x = 3510 now just divide 3510/117 = ???

OpenStudy (anonymous):

30 i did something wrong in my math thanks again :)

OpenStudy (ivettef365):

yw :)

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