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Help please
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\[3^{6n}\le1/81\]
1/81 is the same as 3 to the 4th power
3^4=81
Yes I already put that
so the equation is not true 81<=(1/81)
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I'm trying to solve the equation. .... not see if it's true.
what is unknown in the equation
Is that 3^(6n) <= 1/81 ?
Less than or equal, but yeah that is what I put ^^
\(3^{6n}\le \dfrac{1}{81} \) \( 3^{6n}\le 3^{-4} \)
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6n < -4
Okay, I got it, thanks.
\[3^{6n}\le1/81\] \[6nln(3)\le \ln(1/81)\] \[6n \le \frac{ \ln(1/81) }{ \ln(3) }\] \[n \le ?\]
Do you see the process ?
looks like you got it the easier way, nice.
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