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Mathematics 6 Online
OpenStudy (anonymous):

One of the factors of 3p5 – 12p3 is: p4 p + 2 p2 + 4 4

OpenStudy (ivettef365):

the way you factor that problem is as follows: 3p^5 - 12p^3 3p^3(p^2-4)

OpenStudy (ivettef365):

I don't see on your answers any of the factors

OpenStudy (anonymous):

well your p^2-4 is the difference of two perfect squares so p^2-4 = (p+2)(p-2) so your answer is actual 3p^3(p+2)(p-2) so it is there.

OpenStudy (ivettef365):

that is correct

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