Question

h

Answer 1

\(\bf sin(tan^{-1}(2))\\
tan(\theta) = 2 \implies tan^{-1}(2) = \theta\\
sin(tan^{-1}(2)) \implies sin(\theta)\\
\color{green}{tan(\theta) = 2 \implies \cfrac{\text{opposite}}{\text{adjacent}}\implies \cfrac{b}{a} \implies \cfrac{2}{1}}\\
\color{blue}{c^2 = a^2 + b^2 \implies c = \sqrt{a^2 + b^2} \implies c = \sqrt{5}}\\
sin(tan^{-1}(2)) \implies sin(\theta) \implies \cfrac{\text{opposite}}{\text{hypotenuse}} \implies \cfrac{b}{c} \implies \cfrac{\square?}{\square?}
\)

Answer 2

?

Answer 3

well, what's the sine?

Answer 4

notice the sides, a, b and c there

Answer 5

2/5