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SOMEBODY PLEASE TEACH ME QUADRATIC FORMULA!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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\[\frac{ -b \pm \sqrt(b^2-4ac) }{ 2a }\]
-b+/rootb^2-4ac/2a
The form will be a^2x+bx+c
IK BUT How do you do it.
you just plug in the values
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solve x^2-7x-18=0
OOPS ax^2+bx+c
not for hw just an example for my eoc tomroow
\[x=-b \pm \sqrt{b^2-4ac}\div 2a\] ^_^
x^2-7x-18 a = 1 b=-7 c=-18 plug the values into the equation. You will get two different answers.
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thamksss
np
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