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Help!! will give medal :):) solve for e and f
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|dw:1375235753184:dw|
the 45 below are the angles degree?
correct
ok
e = \[\sqrt{2}\] ......traingle property f = 2 .....pythagoras
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is their any work you could show me to how u got ur answer
tan 45 = opp/adj = e/\[\sqrt{2}\] so e = tan 45 * \[\sqrt{2}\] = \[\sqrt{2}\]
ok thanks
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