Jake's band played songs at three different parties. At the first party they played four-fifths as long as they did at the second party, which was one-half as long as the third party. If they played for 6 minutes at the first party, how many minutes did they play at the third party?

Question

anonymous · Answer

@dumbcow pls help me

dumbcow · Answer

ok so let x,y,z represent 1st party,2nd party,3rd party
x=6
also you are told
x = (4/5)y
y = (1/2)z

make substitutions
6 = 4/5 y
y = 30/4 = 7.5

7.5 = 1/2 z
z = 15

anonymous · Answer

@dumbcow ty so much and ty for the explanation

dumbcow · Answer

yw