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Mathematics 8 Online
OpenStudy (anonymous):

x^2+5x+2=0 quad formula, is x=6, x=-10?

OpenStudy (zzr0ck3r):

well does 6^2+5*6+2 = 0?

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

but in this case is x=6, x=-10

OpenStudy (zzr0ck3r):

form of our equation ax^2+bx+c=0 then \[x=\frac{b\pm\sqrt{b^2-4ac}}{2a}\] a=1, b = 5, c = 2 so \[x=\frac{5\pm\sqrt{25-4*1*2}}{2}=\frac{5\pm\sqrt{17}}{2}\] \[x=\frac{5+\sqrt{17}}{2}\space and \space x=\frac{5-\sqrt{17}}{2} \]

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