use complete sentense to explain the process of graphing f(x)=-x^3+1
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Tagging to many people on OS is considered spamming. Otherwise if you keep on doing this, it will suspend your account. I have been warned once not to do this. Just letting you know. :)
i didnt do that i have no idea who did
i was thinking the same thing to many people
ive been tagged like more than 50 times
Open your heart to Jesus Christ.
i just need help on this one question can anyone help
I'll do. What is it? :)
thank you ut is: The binomial x + 4 is the divisor of 3x3 + 5x2 – 26x + 8. Use complete sentences to explain how you use (either) polynomial division or synthetic division to find the quotient. Be sure to provide this quotient in your answer.
We know you did it @barrelracer1234 and now i will suspend you!
Algebra? Am horrible. Sorry. :(
@abb0t Don't suspend him. He's innocent.
it is ok look at who posted t @abb0t it said someone by the user xfdjerdjyfvd
and i dont apperciate being accused of something i did not do all i did was ask one question that i don not understand
Barrelracer1234 is right. I agree with him.
im a girl btw
never mind.
i am not the one who posted all those names if you look you can see it was not me who posted it
ok i see that but i am not the one who posted it so i am innocent
all i did was ask for help on a question i do not understand and all you are doing is accusing me of something i did not do and i dont apperciate that
i will really would like some help on this one question so i dont have to bother anyone else for the day
can you please help me @claringleek
Yea sure :)
Let x^(1/3) = u ? x^(2/3) = u? Substitute into equation and solve for u ? 3u? + u - 2 = 0 ? 3u? + u - 2 = 0 ? 3u? + 3u - 2u - 2 = 0 ? 3u (u+1) - 2 (u+1) = 0 ? (3u - 2) (u+1) = 0 ? (3u - 2) = 0 or (u + 1) = 0 ? u = 2/3 or -1 From original [ [ substitution x^(1/3) = u ? x^(1/3) = u ? x = u? ? x = (2/3)? or (-1)? ? x = 8/27 or -1 ] ]
Thats what i know but im not suree how to put it in a sentence im still trying though
ok thanks so much i understand this now
lol ok :) its alot yes but i gets easy lol i feel like such a nerd :)
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