Question

Help Please ( See attachment)

Answer 1

{(k+5)/(k2+3k-10)}/{7k-14/4-k2}
{k+5/k2+3k-10}*{4-k2/7k-14}
{k+5/k2+5k-2k-10}*{(2-k)(2+k)/7(2-k)}
{k+5/(k(k+5)-2(+5))*{2+k/7}
{k+5/(k+5)(k-2)}*{2+k/7}
{2+k/7*(k-2)}

Answer 2

Can you get -(1/7) out of the following?\[\frac{(2-k) (k+2) (k+5)}{(k-2) (k+5) (7 k+14)} \]

Answer 3

ya

Answer 4

{(2-k)(k+2)(k+5)}/{(k-2)(k+5)(7k+14)}
{-(k-2)(k+2)(k+5)}/{(k-2)(k+5)7(k+2)}
=-1/7