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find the minimum value of f(x)=(4/5)sin2x-3/5
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hint : the minimum value of the sine of an angle is -1
@cwrw238 so then is the answer just -1 or how do I plug it in?
plug in sin 2x = -1
sine has min value of -1 so (4/5)(-1)-(3/5) =-7/5
@cwrw238 @heybhai ok so even though its like a double angle or something the minimum is always -1?
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yes
always sin and cos always oscillate between 1 and -1
@heybhai @cwrw238 THANK YOU SO MUCH!!!
welcome
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