Question

please help! <3 You! See attachment...----->

Answer 1

reduce to lowest terms

Answer 2

You cant seduce on a math help website. I want to know how to do a problem not get a boyfriend.

Answer 3

the answer is 5

Answer 4

the answer five does not work when i insert it into the problem

Answer 5

well try it again

Answer 6

first solve the fractions, for example you have

5 1 5 + 1(a) 5 + a
---- + ---- = --------- = --------
a 1 a a

Answer 7

then solve the other fraction on the bottom as follows:

a 5 a(a) -5(5) a^2 - 25 (a+5)(a-5)
---- - ----- = ---------- = --------- = -----------
5 a 5a 5a 5a

Answer 8

possible answers:

Answer 9

now you can multiply as follows:

5 + a 5a
----- x ---------
a (a+5)(a-5) now cancel a+5 and the a from 5a

Answer 10

what do you have left

Answer 11

is the asnwer -a/5

Answer 12

\[\frac{ \frac{ 5 }{a }+1 }{\frac{ a }{ 5 }-\frac{ 5 }{ a } }\]
\[\frac{ \frac{25+5a }{5a } }{\frac{ a ^{2}-25}{ 5a } }\]
\[==\frac{ 25+5a }{ 5a }*\frac{ 5a }{a ^{2}-25 }=\frac{ 5\left( 5+a \right) }{ \left( a+5 \right)\left( a-5 \right) }\]
\[=\frac{ 5 }{ a-5 }\]