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Could someone show me how to solve √4x+16= x+1 as an example please? Thank you :)
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wait is it radical 4x?
\(\sqrt{4x}+16= x+1 \ \ ?\)
@jkim3592 aha sorry i keep forgetting to write it like this: √(4x+16) = x + 1
\(\bf \sqrt{4x+16}= x+1 \implies (\sqrt{4x+16})^2= (x+1)^2\)
yep this is right
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@jode0001 @jkim3592 So from the equation that jdoe posted, I solve from there?
yea
@jkim3592 Alrighty, thanks :P
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