Question

find the values ​​of x for which the expression is positive: x^2-1/x^2-3x

Answer 1

\[\frac{ x^2-1 }{ x^2-3x }>0 \]when
\[(x^2-1)(x^2-3x)>0\]

Answer 2

how did you find that?

Answer 3

lol, I see

Answer 4

so x(x-1)(x+1)(x-3)>0

so
\[x \in (-\infty; -1) \cup (0;1) \cup (3;\infty)\]
it's the property of rational numbers