Find the exact solutions of
x^2 - (y - 12)^2 = 144 and y = -x^2
and.. solve the system: y^2 -4x^2 and y = 2x

Question

Find the exact solutions of 
x^2 - (y - 12)^2 = 144 and y = -x^2
and.. solve the system: y^2 -4x^2  and y = 2x

anonymous · Answer

for the first one, solve 
$$x^2-(-x^2-12)^2=144$$

anonymous · Answer

which is the same as 
$$x^2-(x^2+12)^2=144$$ this will have no real zeros, so my guess is there might be a typo in the question

anonymous · Answer

could it be $x^2 +(y - 12)^2 = 144$ ?

anonymous · Answer

I got the answer to the second question - there's not a typo I don't think I'm just not sure what it's asking for?

anonymous · Answer

In the first question that is

anonymous · Answer

there is no real answer for 
x^2 - (y - 12)^2 = 144 and y = -x^2

anonymous · Answer

so what would i write then? no solution? i know i tried to solve the equation myself and it turned out funky.

anonymous · Answer

no real solution

anonymous · Answer

for the second one I got no solution as well, do you agree?

anonymous · Answer

well 0=4, but basically no solution.