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Solve for y. y/4 - (y-1)/2 (> or equal to) 3
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\[\frac{y}{4}-\frac{y-1}{2}\geq 3\] multiply by 4 and get \[y-2(y-1)\geq 6\]
oops \[y-2(y-1)\geq 12\] looks better since \(4\times 3=12\) sorry about that
you good from there or you need help finishing it?
(> or equal to) 10
i doubt it lets check
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remove parentheses and get \[y-2y+2\geq 12\]
combine like terms \[-y+2\geq 12\]
subtract \(2\) and get \[-y\geq 10\]
but you need to solve for \(y\) not \(-y\) change the signs and the inequality to get \[y\leq -10\]
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