Question

Solve triangle EFG given that f=15 , g=18, F=29

Answer 1

Solve for what?

Answer 2

the law on sines

Answer 3

law of sines for this one i think

Answer 4

\[\frac{\sin(29)}{15}=\frac{\sin(G)}{18}\]
\[\sin(G)=\frac{18\sin(29)}{15}\] so
\[G=\sin^{-1}(\frac{18\sin(29)}{15})\]