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solve (x-2)^2 would this equal x^2-4x+4 ?
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yes
\[(x-2)^2\] \[(x-2)(x-2)\] \[x^2 -2x -2x + 4\] \[x^2 -4x + 4\]
@satellite73 i need help with this one What is the area of a square that has a side equal to 2x+1 (A=S^2)
\((2x+1)^2=(2x+1)(2x+1)=?\)
i am sure you can do it, let me know what you get
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4x^2
ok that is the first term there are some more
1) \(2x\times 2x=4x^2\) 2) \(1\times 2x=?\)
4x^2+2x+1?
you missed a \(2x\) in there somewhere
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\[(2x+1)(2x+1)=2x\times 2x+1\times 2x+1\times 2x+1\times 1\]
so its 4x^2+4x+1
or \[4x^2+2x+2x+1\]
yes
thanks c:
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