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Mathematics 21 Online
OpenStudy (anonymous):

Simplify Attatched :))

OpenStudy (anonymous):

OpenStudy (luigi0210):

Get common denominators first

OpenStudy (anonymous):

noooooooo

OpenStudy (luigi0210):

Yessssss

OpenStudy (anonymous):

That requires an immense amount of effort in which I at the moment am not capable of withholding

OpenStudy (dumbcow):

haha ^^ -combine fractions so you have single fractions on top/bottom - when dividing fractions...multiply top by reciprocal of bottom

OpenStudy (anonymous):

you can try to cancel out fraction

OpenStudy (anonymous):

then see if you can work it out from there

OpenStudy (anonymous):

guys Ive been doing math for a solid 14 hours today. I just want an answer pleaseeeeeeeeeeeeeeeeeeeeeeeeeee <3

OpenStudy (dumbcow):

haha 14 hrs straight huh, well then fractions must be easy by now :)

OpenStudy (anonymous):

Nooooooo Help me :'''(

OpenStudy (anonymous):

My Brain B frieeeddd

OpenStudy (luigi0210):

I've been doing math for 6 years

OpenStudy (anonymous):

You are not a female individual who utterly despises the use of any variation whatsoever of math.

OpenStudy (anonymous):

Ans is \[\frac{-5}{2n+1}\]

OpenStudy (anonymous):

I love you

OpenStudy (luigi0210):

Hm, but it could be the wrong answer.. you never know unless you do it yourself

OpenStudy (anonymous):

@Luigi0210 work out the problem you will get the same ans.

OpenStudy (dumbcow):

\[\frac{1}{4n} - \frac{1}{2} = \frac{1-4n}{8n}\] \[\frac{n}{5} -\frac{1}{20n} = \frac{4n^{2} -1}{20n}\] multiply top by reciprocal \[\frac{1-4n}{8n}*\frac{20n}{4n^{2}-1} = \frac{5(1-4n)}{2(4n^{2}-1)}\]

OpenStudy (luigi0210):

Your not even suppose to give it out answers, it's against the CoC

OpenStudy (anonymous):

I dont give a flying flutter

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