Ask your own question, for FREE!
Mathematics 24 Online
OpenStudy (anonymous):

What is the geometric mean of 3 and 15?

hero (hero):

\[x^2 = (3)(15)\]

hero (hero):

Solve for x

hero (hero):

x will only be positive

OpenStudy (anonymous):

\[x ^{2}=45\] am i corrct so far?

OpenStudy (anonymous):

and then wats the next step

OpenStudy (anonymous):

or am i done?

OpenStudy (anonymous):

@Hero

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!