Question

find the solutions to the systems of nonlinear equation


@ivettef365 @primeralph

Answer 1

plug in the y=2x into your bottom equation, you will have \(x^2+(2x)^2=15\) \(\Rightarrow\) \(x^2+4x^2=15\) now solve for "x".

Answer 2

You know from the first equation that y=2x, so lets substitute 2x in for y in the second equation:
\[x^2 + (2x)^2 = 15\]

Answer 3

so i solve x^2+4x^2=15?

Answer 4

@abb0t ?

Answer 5

yES?

Answer 6

Now, you have \(x^2+4x^2=15\) \(\Rightarrow\) \(5x^2=15\) now, divide by 5 to get \(x^2=\frac{15}{5}\) and square root both sides to get \(x= \pm ?\) where "? is the anwer.

Answer 7

square root 3?

Answer 8

Yes.

Answer 9

im right?

Answer 10

Plus or minus square root of 3