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Ten dice are rolled. What is the probability that exactly one die shows a one.
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exactly one?
Exactly one
binomial for this one one "one" and 9 "not ones" \[\binom{10}{1}\left(\frac{1}{6}\right)\times \left(\frac{5}{6}\right)^9\]
Thanks, I had a feeling it would be that ;)
1/6 chance that one of the ten dice is a one. The other five dice each have a 5/6 chance of being something other than one. 1/6 * nine instances of *(5/6)
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