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Mathematics 22 Online
OpenStudy (anonymous):

(1/x+h)-(1/x)

OpenStudy (anonymous):

\[\frac{ 1 }{ x+h }-\frac{ 1 }{ x }\]

OpenStudy (anonymous):

The fractions need to have the same denominator now.

OpenStudy (anonymous):

\[(\frac{ x }{ x })(\frac{ 1 }{ x+h })-(\frac{ 1 }{ x })(\frac{ x+h }{ x+h })\]

OpenStudy (anonymous):

\[\frac{ x }{ x^2+xh }-\frac{ x+h }{ x^2+xh }\]

OpenStudy (anonymous):

Can you solve from there?

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