Question

Find the Maclaurin series for f(x)= e^(-2x) first dy/dx=e^(-2x) second dy/dx=-2e^(-2x) Third dy/dx= 4e^(-2x) Fourth dy/dx=-8e^(-2x) Fifth dy/dx = 16e^(-2x) Sixth dy/dx = -32^(-2x) f(0)=1 f'(0)=-2 f''(0)=4 f'''(0)=-8 f''''(0)=16 f'''''(0)=-32 so when i put it all together I got this.... 1-(2/1!)x + (4/2!)x^2 - (8/3!)x^3 + (16/4!)x^4.....+..... Im just having trouble finishing the problem and writing it out completely