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Fanning and Medal Factor completely: 9x2 + 42x + 49 (3x + 7)(3x − 7) (9x − 7)(9x − 7) (3x + 7)(3x + 7) (9x + 7)(9x + 7)
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9x² + 42x + 49 Find the difference of squares (or the square root of first and last term) 9x²--factor-->3x*3x 49--factor-->7*7 (3x + 7)(3x + 7)
I just want some one to check for me
@satellite73
@Jamierox4ev3r
Good work, you are right @HelloGoodmorning
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You can check yourself whether you are right or not by : (3x+7)(3x+7) = \((3x+7)^2 \\ \text{As : } \space (a+b)^2 = a^2 + 2ab + b^2 \\ (3x+7)^2 = (3x)^2 + 7^2 + 2(3x)(7) = 9x^2 + 49 + 42 x \\ 9x^2 + 42x + 49 \) Hence verified that you are right!
Lol thank you very much
You're welcome ! :)
:)
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