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How do I simplify √x^2+8x+16
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\[\sqrt{x^2+8x+16}\]
can you factorise \(x^2+8x+16\) into a perfect square \((x+a)^2\) ?
\[(x+a)^2=(x+a)(x+a)\\=x(x+a)+a(x+a)\\=x^2+ax+ax+a^2\\=x^2+2ax+a^2\]
tells me in the book that its |x+4|
so a=4 ?
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Don't know, doesn't say what x or a are.
\[ \sqrt{x^2+2ax+a^2}=\sqrt{(x+a)^2}=|x+a|\]
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