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Simplify this: (-3x^-2)^-3
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I believe that the answer is -27x^6
How?
(x)^-n = 1/x^n so in this ex. (-3x^-2)^-3 = (1/-3x^2)^-3 = 1/1/(-3x^2)^3 = 1/1/-27x^6 inverting the fraction and mult. -27x^6
$$(-3x^{-2})^{-3} = (\frac{1}{-3x^2})^{-3} = \frac{1}{\frac{1}{(-3x^2)^3}} = \frac{1}{\frac{1}{-27x^6}} =-27x^6$$
Thanks!
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