Question

If y=..... find second derivative wrt x

Answer 1

\[\Huge y=xe^{x^2}\]

Answer 2

\[\LARGE logy=x^2 logxe\]

Answer 3

do i need to take log again?

Answer 4

There's really not reason to take the log in the first place. Just use the product rule.

Answer 5

\[\log y=\log (xe^{x^2}) \qquad=\qquad \log(x)+\log(e^{x^2}) \qquad=\qquad \log x+x^2 \log e\]

Answer 6

Yah I'm not really sure why the log is being used here :D

Answer 7

okay :(

Answer 8

Don't frown, calculus is fun-ulus!

Answer 9

yup,true

Answer 10

\[\Large y'=\color{royalblue}{\left(x\right)'}e^{x^2}+x\color{royalblue}{\left(e^{x^2}\right)'}\]
Any trouble taking the derivative of that second blue term? :o

Answer 11

nope,i got it ,thanks!