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Given that vector sum A+B+C=0, out of three vectors two are equal in magnitude and the magnitude of third vector is \[\sqrt{2}\] times that of two having equal magnitude. then angle between vectors are given by (i) 30,60,90 (ii)45,135,150 (iii)90,135,150 (iv)90,135,150
Hints: -Vector sum A+B+C = 0 basically tells you that the vectors form a triangle. -Two vectors are equal in magnitude, means two sides of the triangle are equal in length (An isosceles triangle) . -Magnitude of third vector is sqrt(2) times the length of the other two. This makes it an isosceles right triangle. (What is special about the angles in a isosceles right triangle?)
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